泰格豪雅钢链表带怎么拆，泰格豪雅尼龙带怎佩戴

1，泰格豪雅尼龙带怎佩戴

汽车一般开后盖的方法是;都是在汽车驾驶的右下角的车门上有一个开关，只要拉一下就可以开后盖。

同问。。。

泰格豪雅尼龙带怎佩戴

2，豪雅link系列手表表链

泰格豪雅(tag heuer)--概念表系列mikrotimer flying 1000 机械男表

买条皮带去算了

豪雅link系列手表表链

3，单链表拆分成3个循环链表

#include #include #include #include #define list_init_length 10 #define ok 1 typedef int elemtype; typedef struct cirlnode next; cout<<" -> "; //输出单链表元素 } contray_cirl(l); cout<<"逆置后的单链表l如下:"

单链表拆分成3个循环链表

4，怎么拆分链表啊急

首先，弄三个指针(p1,p2，p3)指向原链表head,设你的链表的next属性是指向下个元素的指针,type为存的字符。首先判断p2.type是字母还是数字或是其它，然后p1=p1.next将p1移到下个节点，看p1.type是什么类型，如果与p2.type一致，则p2=p1;p1=p1.next;否则head=p1;然后将p1=p1.next;判断p1.type是什么型，如果和p2.type一致p2.next=p1;p2=p1;p1=p1.next;继续如此判断。三个指针的作用，就是p1判断当前的位置的是否和P2的一致，一致的话，用P2接，不一致的话，用P3去接。接完后，再接第二次。这样就出来了。

给你写了个c++的，应该算是很拉风了，用了动态数组和优先队列实现的最小堆，好喜欢这个程序啊，呜哈哈#include #include using namespace std; void print(priority_queue, greater> &q, size_t size) { for(size_t i = 0; i < size && cout<<<" ";q.pop(), i++); cout< } int main() { int num, *nums; priority_queue, greater> evenlist, oddlist; cin>>num; nums = (int*)calloc(num, sizeof(int)); for(int i = 0; i < num && cin>>nums[i]; nums[i] % 2 == 0 ? evenlist.push(nums[i]) : oddlist.push(nums[i]), i++); cout<<<" "<< print(evenlist, evenlist.size()); print(oddlist, oddlist.size()); return 0; }

5，6链表的拆分和排序

#include<stdio.h>#include <stdlib.h>/*定义链表*/typedef struct node int data; node *next; }NODE; /*创建单链表*/NODE* CreateList(int n) NODE *tmp, *head = NULL, *tail = NULL; int i,num; scanf("%d",&num); head = (NODE*)malloc(sizeof(NODE)); if(head == NULL) printf("No memory available!"); return NULL; } head->data = num; head->next = NULL; tail = head; for(i=0; i<n-1; i++) scanf("%d",&num); tmp = (NODE*)malloc(sizeof(NODE)); if(tmp == NULL) printf("No memory available!"); return NULL; } tmp->data = num; tmp->next = NULL; tail->next = tmp; tail = tmp; } return head; } void CreateEvenList(NODE*head,NODE**nehead,NODE**nohead) int temp,flage,flago; NODE *p,*q,*netail,*notail,*netmp,*notmp; *nehead = (NODE*)malloc(sizeof(NODE)); *nohead = (NODE*)malloc(sizeof(NODE)); netail = *nehead; notail = *nohead; p = head; q = p->next; flage = flago = 0; /*对总链表排序*/ for(p=head; p!=NULL; p=p->next) for(q=p->next; q!=NULL; q=q->next) if(p->data>q->data) temp = p->data; p->data = q->data; q->data = temp; } } } for(p=head; p!=NULL; p=p->next) if(p->data%2==0)/*生成偶数链表*/ netmp = (NODE*)malloc(sizeof(NODE)); netmp->data = p->data; netmp->next = NULL; netail->next = netmp; netail = netmp; flage++; } else/*生成奇数链表*/ notmp = (NODE*)malloc(sizeof(NODE)); notmp->data = p->data; notmp->next = NULL; notail->next = notmp; notail = notmp; flago++; } } if(flage == 0) *nehead=NULL; } if(flago == 0) *nohead=NULL; }} /*计算偶数个数*/int CountNe(NODE *head) int count; NODE *p; count = 0; for(p=head; p!=NULL; p=p->next) if(p->data%2==0) count++; } } return count;}void output(NODE*head) NODE*p; if(head != NULL) for(p=head->next; p!=NULL; p=p->next) printf("%d ",p->data); } printf("\n"); }}int main() int n,ne,no; NODE *head,*nehead,*nohead; scanf("%d", &n); head = CreateList(n); ne = CountNe(head); no = n - ne; printf("%d %d\n",ne,no); CreateEvenList(head,&nehead,&nohead); output(nehead); output(nohead); return 0;}